2021 Day 03

2021/03/README.md

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+# 2021 Day 03: Binary Diagnostic
+Copyright (c) Eric Wastl
+#### [Direct Link](https://adventofcode.com/2021/day/03)
+
+## Part 1
+
+The submarine has been making some odd creaking noises, so you ask it to produce a diagnostic report just in case.
+
+The diagnostic report (your puzzle input) consists of a list of binary numbers which, when decoded properly, can tell you many useful things about the conditions of the submarine. The first parameter to check is the **power consumption**.
+
+You need to use the binary numbers in the diagnostic report to generate two new binary numbers (called the **gamma rate** and the **epsilon rate**). The power consumption can then be found by multiplying the gamma rate by the epsilon rate.
+
+Each bit in the gamma rate can be determined by finding the **most common bit in the corresponding position** of all numbers in the diagnostic report. For example, given the following diagnostic report:
+
+```
+00100
+11110
+10110
+10111
+10101
+01111
+00111
+11100
+10000
+11001
+00010
+01010
+```
+
+Considering only the first bit of each number, there are five `0` bits and seven `1` bits. Since the most common bit is `1`, the first bit of the gamma rate is `1`.
+
+The most common second bit of the numbers in the diagnostic report is `0`, so the second bit of the gamma rate is `0`.
+
+The most common value of the third, fourth, and fifth bits are `1`, `1`, and `0`, respectively, and so the final three bits of the gamma rate are `110`.
+
+So, the gamma rate is the binary number `10110`, or **`22`** in decimal.
+
+The epsilon rate is calculated in a similar way; rather than use the most common bit, the least common bit from each position is used. So, the epsilon rate is `01001`, or **`9`** in decimal. Multiplying the gamma rate (`22`) by the epsilon rate (`9`) produces the power consumption, **`198`**.
+
+Use the binary numbers in your diagnostic report to calculate the gamma rate and epsilon rate, then multiply them together. **What is the power consumption of the submarine**? (Be sure to represent your answer in decimal, not binary.)
+
+## Part 2
+
+Next, you should verify the **life support rating**, which can be determined by multiplying the **oxygen generator rating** by the **CO2 scrubber rating**.
+
+Both the oxygen generator rating and the CO2 scrubber rating are values that can be found in your diagnostic report - finding them is the tricky part. Both values are located using a similar process that involves filtering out values until only one remains. Before searching for either rating value, start with the full list of binary numbers from your diagnostic report and **consider just the first bit** of those numbers. Then:
+
+- Keep only numbers selected by the **bit criteria** for the type of rating value for which you are searching. Discard numbers which do not match the bit criteria.
+- If you only have one number left, stop; this is the rating value for which you are searching.
+- Otherwise, repeat the process, considering the next bit to the right.
+
+The **bit criteria** depends on which type of rating value you want to find:
+
+- To find **oxygen generator rating**, determine the **most common** value (`0` or `1`) in the current bit position, and keep only numbers with that bit in that position. If `0` and `1` are equally common, keep values with a **`1`** in the position being considered.
+- To find **CO2 scrubber rating**, determine the **least common** value (`0` or `1`) in the current bit position, and keep only numbers with that bit in that position. If `0` and `1` are equally common, keep values with a **`0`** in the position being considered.
+
+For example, to determine the **oxygen generator rating** value using the same example diagnostic report from above:
+
+- Start with all 12 numbers and consider only the first bit of each number. There are more `1` bits (7) than `0` bits (5), so keep only the 7 numbers with a `1` in the first position: `11110`, `10110`, `10111`, `10101`, `11100`, `10000`, and `11001`.
+- Then, consider the second bit of the 7 remaining numbers: there are more `0` bits (4) than `1` bits (3), so keep only the 4 numbers with a `0` in the second position: `10110`, `10111`, `10101`, and `10000`.
+- In the third position, three of the four numbers have a `1`, so keep those three: `10110`, `10111`, and `10101`.
+- In the fourth position, two of the three numbers have a `1`, so keep those two: `10110` and `10111`.
+- In the fifth position, there are an equal number of `0` bits and `1` bits (one each). So, to find the **oxygen generator rating**, keep the number with a `1` in that position: `10111`.
+- As there is only one number left, stop; the **oxygen generator rating** is `10111`, or **`23`** in decimal.
+
+Then, to determine the **CO2 scrubber rating** value from the same example above:
+
+- Start again with all 12 numbers and consider only the first bit of each number. There are fewer `0` bits (5) than `1` bits (7), so keep only the 5 numbers with a `0` in the first position: `00100`, `01111`, `00111`, `00010`, and `01010`.
+- Then, consider the second bit of the 5 remaining numbers: there are fewer `1` bits (2) than `0` bits (3), so keep only the 2 numbers with a `1` in the second position: `01111` and `01010`.
+- In the third position, there are an equal number of `0` bits and `1` bits (one each). So, to find the CO2 scrubber rating, keep the number with a `0` in that position: `01010`.
+- As there is only one number left, stop; the **CO2 scrubber rating** is `01010`, or **`10`** in decimal.
+
+Finally, to find the life support rating, multiply the oxygen generator rating (`23`) by the CO2 scrubber rating (`10`) to get **`230`**.
+
+Use the binary numbers in your diagnostic report to calculate the oxygen generator rating and CO2 scrubber rating, then multiply them together. **What is the life support rating of the submarine?** (Be sure to represent your answer in decimal, not binary.)

2021/03/code.py

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+# SPDX-License-Identifier: MIT
+# Copyright (c) 2021 Akumatic
+#
+# https://adventofcode.com/2021/day/03
+
+def read_file() -> list:
+    with open(f"{__file__.rstrip('code.py')}input.txt", "r") as f:
+        return [line for line in f.read().strip().split("\n")]
+
+def get_mcb(vals: list) -> list:
+    bit_count = [sum(int(num[i]) for num in vals) for i in range(len(vals[0]))]
+    return [1 if cnt >= (len(vals) - cnt) else 0 for cnt in bit_count]
+
+def reduce_reports(reports: list, invert: bool = False) -> int:
+    for i in range(0, len(reports[0])):
+        mcb = get_mcb(reports)[i]
+        bit = str(mcb if not invert else 1 - mcb)
+        reports = [rep for rep in reports if rep[i] == bit]
+        if len(reports) == 1:
+            break
+    return int(reports[0], 2)
+
+def part1(vals: list) -> int:
+    mcb = get_mcb(vals)
+    gamma = "".join(["1" if bit else "0" for bit in mcb])
+    epsilon = "".join(["0" if bit else "1" for bit in mcb])
+    return int(gamma, 2) * int(epsilon, 2)
+            
+def part2(vals: list) -> int:
+    ogr = reduce_reports(vals[:]) # oxygen generator rating
+    csr = reduce_reports(vals[:], invert=True) # CO2 scrubber rating
+    return ogr * csr
+
+if __name__ == "__main__":
+    vals = read_file()
+    print(f"Part 1: {part1(vals)}")
+    print(f"Part 2: {part2(vals)}")

2021/03/solution.txt

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+Part 1: 845186
+Part 2: 4636702

2021/03/test_code.py

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+# SPDX-License-Identifier: MIT
+# Copyright (c) 2021 Akumatic
+
+from code import part1, part2
+
+def test():
+    vals = ["00100", "11110", "10110", "10111", "10101", "01111",
+        "00111", "11100", "10000", "11001", "00010", "01010"]
+    assert part1(vals) == 198
+    print("Passed Part 1")
+    assert part2(vals) == 230
+    print("Passed Part 2")
+
+if __name__ == "__main__":
+    test()

2021/README.md

@@ -17,6 +17,7 @@ Collect stars by solving puzzles. Two puzzles will be made available on each day
 | --- | --- | --- |---| --- |
 | 01 | :white_check_mark: | :white_check_mark: | [Solution](01/code.py) | [Day 01](https://adventofcode.com/2021/day/1) |
 | 02 | :white_check_mark: | :white_check_mark: | [Solution](02/code.py) | [Day 02](https://adventofcode.com/2021/day/2) |
+| 03 | :white_check_mark: | :white_check_mark: | [Solution](03/code.py) | [Day 03](https://adventofcode.com/2021/day/3) |
 | 03 |  |  |  |  |
 | 04 |  |  |  |  |
 | 05 |  |  |  |  |